標題:
3題有關圓形的數學題...請智者們幫手
發問:
最佳解答:
幅圖太細喇...... 2007-01-28 17:16:24 補充： 你補充幅圖都係咁細...... 2007-01-29 02:13:32 補充： Assume length of OR as y, length of QR as x,and we have angle ORQ = angle ORP = 90degso OR^2 QR^2 = OQ^2 - (1)and OR^2 PR^2 = OP^2 - (2) 2007-01-29 02:13:43 補充： From (1), we have y^2 x^2 = 5^2From (2), we have y^2 (2x)^2 = 13^2(2)-(1), we have 3x^2 = 144, i.e. x=sqrt48=4(sqrt3)So, the length of RT = the length of PR = 2x = 8(sqrt3)
其他解答:
你的圖太小啦！請你把圖放大好嗎？
3題有關圓形的數學題...請智者們幫手
發問:
此文章來自奇摩知識+如有不便請留言告知
唔識計↓ http://img0703.paintedover.com/uploads/0703/2_29.jpg 請各位智者幫幫助!! 更新: http://img0703.paintedover.com/uploads/0703/2_29_1.jpg 更新 2: http://i151.photobucket.com/albums/s146/keko_811/55.jpg?t=1169978499 應該會大些了....最佳解答:
幅圖太細喇...... 2007-01-28 17:16:24 補充： 你補充幅圖都係咁細...... 2007-01-29 02:13:32 補充： Assume length of OR as y, length of QR as x,and we have angle ORQ = angle ORP = 90degso OR^2 QR^2 = OQ^2 - (1)and OR^2 PR^2 = OP^2 - (2) 2007-01-29 02:13:43 補充： From (1), we have y^2 x^2 = 5^2From (2), we have y^2 (2x)^2 = 13^2(2)-(1), we have 3x^2 = 144, i.e. x=sqrt48=4(sqrt3)So, the length of RT = the length of PR = 2x = 8(sqrt3)
其他解答:
你的圖太小啦！請你把圖放大好嗎？
文章標籤
全站熱搜
留言列表
