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Physics Question!!!20PTS!!!Thx

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發問:

A horizontal wire is stretched with a tension of 88.0 N , and the speed of transverse waves for the wire is 492 m/s. What must the amplitude of a traveling wave of frequency 68.0 Hz be in order for the average power carried by the wave to be 0.365 W ?

最佳解答:

Use equation, v^2 = T/p where v is the speed of wave on the string, T is the string tension, and p is the linear density (mass per unit length) of the string. hence, 492^2 = 88/p p = 88/492^2 kg/m = 3.64 x 10^-4 kg/m Average power carried by the wave along the string = (1/2)pv(wA)^2 where w is the angular of the wave, and A is the amplitude Therefore, 0.365 = (1/2).(3.64x10^-4).(492).[(2.pi.68)A]^2 solve for A gives A = 4.73 x 10^-3 m

其他解答:554581090DCCD3AC

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