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標題:
急ar!!plz About the IR calculation frequency and wavenumber
發問:
Calculate approximate frequency and wavenumber of the C-H stretching vibration knowing that the force constant of C-H bond k = 500 N m-1. To which part of the electromagnetic spectrum would this frequency belong?Note that carbon atom is much heavier than hydrogen atom.v= 1/2π √(k/m eff)(h =... 顯示更多 Calculate approximate frequency and wavenumber of the C-H stretching vibration knowing that the force constant of C-H bond k = 500 N m-1. To which part of the electromagnetic spectrum would this frequency belong? Note that carbon atom is much heavier than hydrogen atom. v= 1/2π √(k/m eff) (h = 6.626 x 10-34 J s; c = 2.998 x 108 m s-1; NA = 6.022 x 1023 mol-1) Thank you very much
最佳解答:
Since the carbon atom is much heavier than hydrogen atom, meff can be approximated as the mass of a single H atom = 1.66 x 10-27 kg. Hence v = (1/2π) √(500/1.66 x 10-27) = 8.733 x 1013 Hz And the wavelength is: c/v = 2.998 x 108/8.733 x 1013 = 3.433 x 10-6 m or 3.433 x 10-4 cm Finally the wavenumber is 1/3.433 x 10-4 = 2913 cm-1.
其他解答:6A560DB68EC65D60
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